If f(x) = 3x^2 - 5x + 2, what is the equation of the line tangent to f(x) at x = 1?

Core Concept

To find the equation of the tangent line, we need two things: the point of tangency and the slope at that point. First, find f(1) = 3(1)^2 - 5(1) + 2 = 0, so the point is (1, 0). Next, find the derivative f'(x) = 6x - 5. At x = 1, f'(1) = 6(1) - 5 = 1, so the slope is 1. Using point-slope form: y - 0 = 1(x - 1), which simplifies to y = x - 1. Therefore, the correct answer is B.