Apentix/AP Calculus AB/Unit 1: Limits and Continuity/Question
AP Calculus ABhardmcq1 pt

If f(x) = |x-3|/(x-3), then lim(x→3⁻) f(x) is:

A.Does not exist
B.-1
C.0
D.1

Explanation

Core Concept

As x→3⁻, x-3 < 0, so |x-3| = -(x-3). Therefore f(x) = -(x-3)/(x-3) = -1 for x < 3, so lim(x→3⁻) f(x) = -1.

Correct Answer

B-1

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