AP Calculus ABeasymcq1 pt
If f(x) = 3x^4 - 2x^3 + 5x - 7, then f'(x) = ?
A.A) 12x^3 - 6x^2 + 5
B.B) 12x^3 - 6x^2 + 5x
C.C) 12x^3 - 6x^2 - 5
D.D) 3x^3 - 2x^2 + 5
Using the power rule for differentiation, we bring down the exponent and multiply it by the coefficient, then reduce the exponent by 1 for each term. For 3x^4, we get 12x^3. For -2x^3, we get -6x^2. For 5x, we get 5. The derivative of a constant (-7) is 0. So f'(x) = 12x^3 - 6x^2 + 5, which is option A. Option B is incorrect because it has an extra x in the last term. Option C is incorrect because it has a negative sign for the last term. Option D is incorrect because it doesn't apply the power rule correctly.
AA) 12x^3 - 6x^2 + 5
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