AP Calculus ABmediummcq1 pt
If f(x) = sin(3x^2), then f'(x) =
A.B) 6x cos(3x^2)
B.A) cos(3x^2)
C.C) 3 cos(3x^2)
D.D) 6x sin(3x^2)
This requires the chain rule. The derivative of sin(u) is cos(u) · u', where u = 3x^2. So f'(x) = cos(3x^2) · 6x = 6x cos(3x^2).
AB) 6x cos(3x^2)
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