AP Calculus ABmediummcq1 pt
If y = x³ + 2xy + y² = 3, find dy/dx using implicit differentiation:
A.(-3x²)/(2x + 2y)
B.(3x² + 2y)/(2x + 2y)
C.(-3x² - 2y)/(2x + 2y)
D.(3x²)/(2x + 2y)
Differentiating: 3x² + 2y + 2x(dy/dx) + 2y(dy/dx) = 0. Solving: (2x + 2y)dy/dx = -3x² - 2y, so dy/dx = (-3x² - 2y)/(2x + 2y).
C(-3x² - 2y)/(2x + 2y)
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