A particle moves along a straight line with position function s(t) = t^3 - 6t^2 + 9t, where t is measured in seconds and s(t) is measured in meters. What is the acceleration of the particle at t = 2 seconds?

Core Concept

To find acceleration, we need to find the second derivative of the position function. First, find velocity: v(t) = s'(t) = 3t^2 - 12t + 9. Then find acceleration: a(t) = v'(t) = 6t - 12. At t = 2: a(2) = 6(2) - 12 = 0 m/s².