AP Calculus ABmediummcq1 pt
The absolute maximum of f(x) = x³ - 3x on the interval [-2, 2] occurs at:
A.x = -1
B.x = 2
C.x = -2
D.x = 1
f'(x) = 3x² - 3 = 0 → x = ±1. f(-2) = -8+6 = -2, f(-1) = -1+3 = 2, f(1) = 1-3 = -2, f(2) = 8-6 = 2. The absolute maximum is 2, occurring at x = -1 and x = 2.
Cx = -2
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