AP Calculus ABmediummcq1 pt
∫ 1/(1+x²) dx =
A.-1/(1+x²) + C
B.arctan(x) + C
C.arcsin(x) + C
D.ln(1+x²) + C
Explanation
Core Concept
The integral of 1/(1+x²) is arctan(x) + C. This is a standard inverse trigonometric integral formula.
Correct Answer
Barctan(x) + C
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