AP Chemistrymediummcq1 pt
What volume of 0.5 M HCl is needed to prepare 500 mL of 0.1 M HCl?
A.250 mL
B.100 mL
C.200 mL
D.50 mL
Using M₁V₁ = M₂V₂: (0.5 M)(V₁) = (0.1 M)(500 mL), so V₁ = (0.1 × 500)/0.5 = 100 mL. Dilute 100 mL of 0.5 M HCl to 500 mL total volume.
B100 mL
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