AP Chemistryhardmcq1 pt
If ΔH° = +180 kJ and ΔS° = +200 J/K for a reaction at 298 K, then ΔG° is:
A.+120.4 kJ
B.-239.6 kJ
C.-120.4 kJ
D.+239.6 kJ
ΔG° = ΔH° - TΔS° = 180,000 - 298(200) = 180,000 - 59,600 = +120,400 J = +120.4 kJ. Positive ΔG° means the reaction is non-spontaneous at 298 K.
A+120.4 kJ
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