A ball is thrown vertically upward with an initial velocity of 20 m/s. What is the maximum height reached by the ball?

Core Concept

Using the kinematic equation v² = u² + 2as, where v = 0 m/s (at maximum height), u = 20 m/s (initial velocity), and a = -9.8 m/s² (acceleration due to gravity), we can solve for s (displacement). 0 = (20)² + 2(-9.8)s → 0 = 400 - 19.6s → 19.6s = 400 → s ≈ 20.4 m, which is approximately 20 m.