AP Physics 1easymcq1 pt
A ball is thrown vertically upward with an initial velocity of 20 m/s. What is the maximum height reached by the ball? (Take g = 10 m/s²)
A.A) 10 m
B.B) 20 m
C.D) 200 m
D.C) 40 m
At maximum height, the final velocity is 0 m/s. Using the kinematic equation v² = u² + 2as, where v = 0, u = 20 m/s, and a = -g = -10 m/s², we get 0 = (20)² + 2(-10)s, which simplifies to 0 = 400 - 20s. Solving for s, we get s = 20 m. Option A is incorrect as it would be the result if we used v = u + at with t = 1 s. Option C is incorrect as it would be the result if we used v = u + at with t = 2 s. Option D is incorrect as it would be the result if we forgot to divide by 2 in the kinematic equation.
BB) 20 m
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