Two objects are thrown vertically upward from the same height with different initial velocities. Object A is thrown with an initial velocity of 20 m/s, and Object B is thrown with an initial velocity of 30 m/s. How much higher does Object B go than Object A?

Core Concept

The maximum height of an object thrown vertically upward is given by h = v₀²/(2g), where v₀ is the initial velocity and g is the acceleration due to gravity. For Object A: h_A = (20)²/(2×9.8) = 400/19.6 ≈ 20.4 m. For Object B: h_B = (30)²/(2×9.8) = 900/19.6 ≈ 45.9 m. The difference in height is h_B - h_A = 45.9 - 20.4 = 25.5 m, which rounds to 25 m.