AP Physics 1easymcq1 pt

A 2.0 kg block is pushed along a horizontal surface by a force of 10 N at an angle of 30 degrees above the horizontal. The block moves a distance of 5.0 m. What is the work done by the applied force?

A.C) 50 J
B.B) 43.3 J
C.D) 100 J
D.A) 25 J

Explanation

Core Concept

The work done by a force is given by W = F·d·cos(θ), where F is the force magnitude, d is the displacement, and θ is the angle between the force and displacement vectors. Here, W = 10 N × 5.0 m × cos(30°) = 50 × 0.866 = 43.3 J.

Correct Answer

BB) 43.3 J

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