AP Physics 1hardmcq1 pt

A pendulum consists of a bob of mass m attached to a string of length L. It is released from rest at an angle θ from the vertical. What is the speed of the bob at its lowest point?

A.D) √(2gL cosθ)
B.B) √(2gL(1-cosθ))
C.A) √(gL(1-cosθ))
D.C) √(gL cosθ)

Explanation

Core Concept

Using conservation of energy, the potential energy at the initial position equals the kinetic energy at the lowest point. The height difference is h = L(1-cosθ). So mgh = (1/2)mv², which gives v = √(2gh) = √(2gL(1-cosθ)).

Correct Answer

BB) √(2gL(1-cosθ))

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