AP Physics 1mediummcq1 pt

A spring with spring constant k = 800 N/m is compressed by 0.2 m from its equilibrium position. A block of mass 2 kg is placed in contact with the spring and then released. What is the maximum speed of the block as it moves along a horizontal frictionless surface?

A.C) 8.0 m/s
B.D) 16.0 m/s
C.B) 4.0 m/s
D.A) 2.0 m/s

Explanation

Core Concept

The potential energy stored in the spring is (1/2)kx² = (1/2)(800 N/m)(0.2 m)² = 16 J. When released, this potential energy converts to kinetic energy of the block: (1/2)mv² = 16 J. Solving for v: v = √(2×16 J/2 kg) = √(16) = 4.0 m/s.

Correct Answer

CB) 4.0 m/s

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