AP Physics 2easymcq1 pt

A copper wire has a length of 2.0 m and a cross-sectional area of 1.0 × 10^-6 m². If the resistivity of copper is 1.7 × 10^-8 Ω·m, what is the resistance of the wire?

A.C) 2.0 × 10^-2 Ω

B.D) 1.7 × 10^-8 Ω

C.B) 3.4 × 10^-2 Ω

D.A) 3.4 × 10^-8 Ω

Explanation

Core Concept

The resistance of a wire is calculated using the formula R = ρL/A, where ρ is the resistivity, L is the length, and A is the cross-sectional area. Substituting the given values: R = (1.7 × 10^-8 Ω·m)(2.0 m)/(1.0 × 10^-6 m²) = 3.4 × 10^-2 Ω.

Correct Answer

CB) 3.4 × 10^-2 Ω

Practice more AP Physics 2 questions with AI-powered explanations

Practice Unit 4: Electric Circuits Questions →