AP Physics 2easymcq1 pt
A solenoid with 100 turns per centimeter carries a current of 2.0 A. What is the magnetic field strength inside the solenoid?
A.A) 0.025 T
B.C) 2.5 T
C.D) 25 T
D.B) 0.25 T
Explanation
Core Concept
The magnetic field inside a solenoid is given by B = μ₀nI, where μ₀ is the permeability of free space (4π × 10^-7 T·m/A), n is the number of turns per unit length, and I is the current. First, convert n to turns per meter: n = 100 turns/cm × 100 cm/m = 10,000 turns/m. Then, B = (4π × 10^-7 T·m/A)(10,000 turns/m)(2.0 A) = 0.25 T.
Correct Answer
DB) 0.25 T
Practice more AP Physics 2 questions with AI-powered explanations
Practice Unit 5: Magnetism and Electromagnetic Induction Questions →