AP Physics 2hardmcq1 pt
A diffraction grating has 5000 lines per cm. When illuminated with monochromatic light of wavelength 600 nm, what is the angle for the second-order maximum?
A.D) 69.1°
B.C) 34.4°
C.A) 8.6°
D.B) 17.2°
The diffraction grating equation is d sinθ = mλ, where d is the spacing between lines, m is the order, and λ is the wavelength. First, find d = 1/5000 cm = 2×10^-6 m. For m=2 and λ=600 nm=6×10^-7 m, we get sinθ = (2 × 6×10^-7)/(2×10^-6) = 0.6. Therefore, θ = arcsin(0.6) = 17.2°.
DB) 17.2°
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