AP Physics 2hardmcq1 pt
Light of wavelength 450 nm passes through a single slit of width 0.1 mm. What is the width of the central maximum on a screen 2 m away?
A.A) 0.9 cm
B.C) 3.6 cm
C.B) 1.8 cm
D.D) 7.2 cm
The width of the central maximum in single-slit diffraction is given by w = 2λL/a, where λ = 450 nm = 4.5×10^-7 m, L = 2 m, and a = 0.1 mm = 1×10^-4 m. Therefore, w = 2 × 4.5×10^-7 × 2 / 1×10^-4 = 1.8×10^-2 m = 1.8 cm.
CB) 1.8 cm
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