AP Calculus ABhardmcq1 pt

The position of a particle moving along a straight line is given by s(t) = t³ - 6t² + 9t for t ≥ 0. What is the average rate of change of the particle's position on the interval [0, 3]?

Explanation

Core Concept

The average rate of change is [s(3) - s(0)]/[3 - 0] = [(27 - 54 + 27) - (0)]/3 = 0/3 = 0. The particle returns to its starting position after 3 time units.

Correct Answer

rate-0

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