AP Calculus ABhardmcq1 pt

A particle moves along the $x$-axis so that its velocity at time $t \ge 0$ is given by $v(t) = t^2 - 5t + 6$. At time $t = 1.5$, is the speed of the particle increasing or decreasing, and why?

Explanation

Core Concept

Correct. The velocity is $v(1.5) = 0.75 > 0$ and acceleration is $a(1.5) = -2 < 0$. When velocity and acceleration have opposite signs, the speed of the particle is decreasing.

Correct Answer

q2_a

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