AP Calculus ABhardmcq1 pt
Explanation
Core Concept
Correct. By the Mean Value Theorem, since $f$ is continuous on $[-2, 5]$ and differentiable on $(-2, 5)$, there must exist a $c$ in $(-2, 5)$ such that $f'(c) = \frac{f(5) - f(-2)}{5 - (-2)} = \frac{22 - 1}{7} = 3$.
Correct Answer
q1_a
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