AP Calculus BCmediumstimulus-mcq1 pt
Explanation
Core Concept
Since $f$ is continuous on $[1, 6]$, it is continuous on $[1, 3]$. Because $f(1) = -4 < 0$ and $f(3) = 2 > 0$, the Intermediate Value Theorem guarantees at least one root in the interval $(1, 3)$.
Correct Answer
ivt_1_3
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